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6y^2+25y+21=0
a = 6; b = 25; c = +21;
Δ = b2-4ac
Δ = 252-4·6·21
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{121}=11$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-11}{2*6}=\frac{-36}{12} =-3 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+11}{2*6}=\frac{-14}{12} =-1+1/6 $
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